Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 505: 127

Answer

$12.5\,rotations/hr$

Work Step by Step

$\frac{75^{\circ}}{1\,min}=\frac{75^{\circ}}{1\,min}\times\frac{60\,min}{1\,hr}\times\frac{1\,rotation}{360^{\circ}}=12.5\,rotations/hr$
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