Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 503: 22

Answer

(a) $49^\circ 19'10''$ (b) $129^\circ 19'10''$

Work Step by Step

(a) For the complement, we have $\alpha=90^\circ-50^\circ 40'50''=89^\circ59'60''-50^\circ 40'50''=49^\circ 19'10''$ (b) For the supplement, we have $\beta=180^\circ-50^\circ 40'50''=179^\circ59'60''-50^\circ 40'50''=129^\circ 19'10''$
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