Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 503: 19

Answer

(a)$75^{\circ}40^{\prime}$ (b)$165^{\circ}40^{\prime}$

Work Step by Step

(a) We can find the compliment by subtracting the given angle value from $90^{\circ}$ and we know that $90^{\circ}=89^{\circ}60^{\prime}$ $89^{\circ}60^{\prime}-14^{\circ}20^{\prime}=75^{\circ}40^{\prime}$ (b) We can find the supplement by subtracting the given angle value from $180^{\circ}$ and we know that $180^{\circ}=179^{\circ}60^{\prime}$ $179^{\circ}60^{\prime}-14^{\circ}20^{\prime}=165^{\circ}40^{\prime}$
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