Answer
Graph-B.
Work Step by Step
Given $y=log_3(x+2)$, let $x=1$, we have $y=log_3(1+2)=1$, A and B fit. Let $x=-1$, we have $y=log_3(-1+2)=0$, only B fits. We can also view graph-B as a result of shifting 2 units to the left from $log_3(x)$
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