Answer
$f^{-1}(x)=5^x$
Work Step by Step
1. Rewrite the function as $y=log_5(x)$
2. Exchange $x,y$ to get $x=log_5(y)$
3. Solve for $y$ to get $y=5^x$
4. Replace $y$ with $f^{-1}(x)$ to get $f^{-1}(x)=5^x$
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