Answer
$\{\pm2i,\pm5i \}$
Work Step by Step
Step 1. Let $u=x^2$, we need to solve $u^2+29u+100=0$ or $(u+4)(u+25)=0$ which gives $u=-4,-25$
Step 2. For $u=-4$, we have $x^=-4$ and $x=\pm2i$
Step 3. For $u=-25$, we have $x^=-25$ and $x=\pm5i$
Step 4. The zeros are $\{\pm2i,\pm5i \}$