Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 3 - Polynomial and Rational Functions - 3.3 Zeros of Polynomial Functions - 3.3 Exercises - Page 338: 120

Answer

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Work Step by Step

Step 1. Let $c=x+yi$, we have $c^2=x^2-y^2+(2xy)i$ and $\overline{c^2}=x^2-y^2-(2xy)i$ Step 2. We have $\overline{c}=x-yi$ and $(\overline{c})^2=x^2-y^2-(2xy)i$ Step 3. Thus we have $\overline{c^2}=(\overline{c})^2$
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