Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises: 7

Answer

$\color{blue}{(x+2)^2+(y-3)^2=225}$

Work Step by Step

RECALL: The center-radius form of a circle whose center is at $(h, k)$ and whose radius is $r$ units is: $(x-h)^2+(y-k)^2=r^2$ The given circle has its center at $(-2, 3)$ and has a radius of 15 units. Thus, its equation in center-radius form is : $(x-(-2))^2+(y-3)^2=15^2 \\\color{blue}{(x+2)^2+(y-3)^2=225}$
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