Chapter 2 - Graphs and Functions - Chapter 2 Test Prep - Review Exercises - Page 296: 5

$(22,-6)$

Step 1. Assume the coordinates of B is $B(x,y)$, the midpoint formula for AB gives $(\frac{x-6}{2},\frac{y+10}{2})$ Step 2. Let $\frac{x-6}{2}=8$, we have $x=22$ Step 3. Let $\frac{y+10}{2}=2$, we have $y=-6$ Step 4. Thus we have $B(22,-6)$