Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 291: 109

Answer

$\color{blue}{\bf{(a) N(x)=100-x }}$ $\color{blue}{\bf{(b) G(x)=20 +5x }}$ $\color{blue}{\bf{(c) C(x)=(100-x)(20 +5x) }}$ $\color{blue}{\bf{(d) $9600 }}$

Work Step by Step

100 people or fewer attend a party, $x$ is the number less than 100 that attend, or $x=100 - \text{ number of attendees}$. $\bf{(a)}$ The number of attendees $N$ can be modeled as a function of the number of people who don't attend, $x$. $\color{blue}{\bf{N(x)=100-x }}$ $\bf{(b)}$ if 100 people attend, it costs $20$ per guest, if less than 100 people attend the cost is $5$ extra per guest. The cost for each guest is modeled as $G(x)$ $\color{blue}{\bf{G(x)=20 +5x }}$ $\bf{(c)}$ Multiplying the formula for the number of people who attend, $N(x)$, by the formula for the cost for each guest,$G(x)$ gives us the total cost $C(x)$. $C(x)=N(x)*G(x)$ $\color{blue}{\bf{C(x)=(100-x)(20 +5x) }}$ $\bf{(d)}$ if $80$ people attend: $x=100-80$ $x=20$ $C(20)=(100-20)(20 +5(20))$ $C(20)=(100-20)(20 +100)$ $C(20)=(80)(120)$ $\color{blue}{\bf{$9600 }}$
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