Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 291: 110

Answer

$\color{blue}{\bf{(a) y_1=x(0.02) }}$ $\color{blue}{\bf{(b) y_2=(x+500)(0.015) }}$ $\color{blue}{\bf{(c) y_1+y_2}}$$\color{blue}{\text{ is the combined interest of the two savings accounts} }$ $\color{blue}{\bf{(d) {$}16.25} }$

Work Step by Step

$\bf{(a)}$ $y_1$ is the interest from the first savings account where $x$ dollars are deposited at $2%$% simple interest $\color{blue}{y_1=x(0.02)}$ $\bf{(b)}$$y_2$ is the interest from the second savings account where ${$}$500 more than the first account are deposited at $1.5$% simple interest $\color{blue}{y_2=(x+500)(0.015)}$ $\bf{(c)}$ $\color{blue}{y_1+y_2 \text{is the combined interest of the two savings accounts}}$ $\bf{(d)}$ If ${$}$250 is deposited in the first account, the total interest is: $y_1(250)+y_2(250)$ $(250)(0.02)+(250+500)(0.015)$ $5+11.25$ $\color{blue}{{$}16.25}$
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