Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 288: 36

Answer

$\color{blue}{\bf{( a ) 4 } }$ $\color{blue}{\bf{( b ) -2 } }$ $\color{blue}{\bf{( c ) 3 } }$ $\color{blue}{\bf{( d ) -3 } }$

Work Step by Step

$\bf{(a)}$We are given a graph and asked to find: $(f+g)( 1 )$ $f( 1 )+g( 1 )$ From the given graph we see that: $y=f( 1 )= 3 $ and $y=g( 1 )= 1 $ $ 3 + 1 $ $\color{blue}{\bf{ 4 } }$ $\bf{( b )}$We are asked to find: $( f-g )( 0 )$ $f( 0 )-g( 0 )$ From the given graph we see that: $y=f( 0 )= -2 $ and $y= g( 0 )= 0 $ $ -2 - 0 $ $\color{blue}{\bf{ -2 } }$ $\bf{( c )}$We are asked to find: $( fg )( -1 )$ From the given graph we see that: $y= f( -1 )= $ and $y=g( -1 )= $ $( -3 )( -1 )$ $\color{blue}{\bf{ 3 } }$ $\bf{( d )}$We are asked to find: $( \dfrac{f}{g} )( 1 )$ From the given graph we see that: $y=f( 1 ) = -3 $ and $y=g( 1 )= 1 $ $\dfrac{ -3 }{ 1 }$ $\color{blue}{\bf{ -3 }}$
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