Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.8 Function Operations and Composition - 2.8 Exercises - Page 288: 35

Answer

$\color{blue}{\bf{( a ) 3 } }$ $\color{blue}{\bf{( b ) -5 } }$ $\color{blue}{\bf{( c ) 2 } }$ $\color{blue}{\bf{( d ) undefined } }$

Work Step by Step

$\bf{(a)}$We are given a graph and asked to find: $(f+g)( -1 )$ $f( -1 )+g( -1 )$ From the given graph we see that: $y=f( -1 )= 0 $ and $y=g( -1 )= 3 $ $ 0 + 3 $ $\color{blue}{\bf{ 3 } }$ $\bf{( b )}$We are asked to find: $( f-g )( -2 )$ $f( -2 )-g( -2 )$ From the given graph we see that: $y=f( -2 )= -1 $ and $y= g( -2 )= 4 $ $ -1 - 4 $ $\color{blue}{\bf{ -5 } }$ $\bf{( c )}$We are asked to find: $( fg )( 0 )$ From the given graph we see that: $y= f( 0 )= 1 $ and $y=g( 0 )= 2 $ $( 1 )( 2 )$ $\color{blue}{\bf{ 2 } }$ $\bf{( d )}$We are asked to find: $( \dfrac{f}{g} )( 2 )$ From the given graph we see that: $y=f( 2 ) = 3 $ and $y=g( 2 )= 0 $ $\dfrac{ 3 }{ 0 }$ $\color{blue}{\bf{ undefined }}$
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