#### Answer

domain: is $(-\infty, +\infty)$
range: $(-\infty, +\infty)$

#### Work Step by Step

The given line can be graphed using the x and y-intercepts.
RECALL:
(1) The x-intercept can be found by setting $y=0$ then solving for $x$.
(2) The y-intercept can be found by setting $x=0$ then solving for $y$.
Find the x-intercept of the given equation. Set $y=0$ then solve for $x$ to obtain:
\begin{array}{ccc}
\\&3y-4x&=&0
\\&3(0)-4x&=&0
\\&-4x&=&0
\\&\frac{-4x}{-4}&=&\frac{0}{-4}
\\&x&=&0
\end{array}
The x-intercept is $(5, 0)$.
Find the x-intercept of the given equation. Set $x=0$ then solve for $y$ to obtain:
\begin{array}{ccc}
\\&3y-4x&=&0
\\&3y-4(0)&=&0
\\&3y&=&0
\\&\frac{3y}{3}&=&\frac{0}{3}
\\&y&=&0
\end{array}
The y-intercept is $(0, 0)$.
The intercepts are the same so one more point is needed to graph the line.
Set $x=3$ then solve for $y$ to obtain:
$3y-4x=0
\\3y-4(3)=0
\\3y-12=0
\\3y=12
\\\frac{3y}{3}=\frac{12}{3}
\\y=4$
The line contains the point $(3, 4)$.
Graph the line by plotting $(0, 0)$ and $(3, 4)$ and connecting them using a line.
(Refer to the graph in the answer part above.)
The graph covers all x-values therefore the domain is $(-\infty, +\infty)$.
The graph covers all y-values therefore the range is $(-\infty, +\infty)$.