Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 2 - Graphs and Functions - 2.4 Linear Functions - 2.4 Exercises - Page 228: 28

Answer

domain: $\left\{2\right\}$ range:$\left\{-\infty, +\infty\right\}$ Refer to the graph below. The line contains the points $(2, 0)$ and $(2, 3)$. Plot the points above and connect them using a line. (Refer to the graph in the answer part above.)

Work Step by Step

Solve for $x$ to obtain: $-3x+6=0 \\-3x+6-6=0-6 \\-3x=-6 \\\frac{-3x}{-3}=\frac{-6}{-3} \\x=2$ This means the given equation is equivalent to $x=2$. RECALL: The line $x=a$, where $a$ is a real number:: (a) is vertical. All points on this line have an x-coordinate of $a$; (b) has the set of real numbers as its range; and (c) has a domain of $\left\{a\right\}$ Thus, the graph of the equation $x=2$ is a vertical line. All points on the line have an x-coordinate of $2$. The domain is $\left\{2\right\}$. The range is $\left\{-\infty, +\infty\right\}$. The line contains the points $(2, 0)$ and $(2, 3)$. Plot the points above and connect them using a line. (Refer to the graph in the answer part above.)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.