Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - Chapter 1 Test Prep - Review Exercises - Page 179: 98

Answer

$(-\frac{1}{3},0)$

Work Step by Step

Step 1. Rewrite the inequality as $\frac{5x+2}{x}+1\lt0\longrightarrow \frac{5x+2+x}{x}\lt0\longrightarrow \frac{6x+2}{x}\lt0$ Step 2. Identify the boundary points $x=-\frac{1}{3},0$ and separate the number line into intervals $(-\infty, -\frac{1}{3})$, $(-\frac{1}{3},0)$, and $(0,\infty)$ Step 3. Use test points $x=-1,-\frac{1}{6},1$ to get the signs of the left side of the inequality as $+,-,+$ Step 4. Based on the signs, we have the solution as $(-\frac{1}{3},0)$
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