Answer
$[-\frac{8}{9} ,\infty)$
Work Step by Step
Given $11x\geq2(x-4)$, we have $11x\geq2x-8\longrightarrow 9x\geq-8\longrightarrow x\geq-\frac{8}{9}$ or in interval notation $[-\frac{8}{9} ,\infty)$
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