Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 133: 49

Answer

(a) $108.1\ million$ (b) $2004$

Work Step by Step

(a) Given $y=0.2313x^2+2.600x+35.17$. for year 2007, we have $x=2007-1994=13$, thus $y=0.2313(13)^2+2.600(13)+35.17\approx108.1\ million$ (b) Let $y=90$, we have $90=0.2313x^2+2.600x+35.17$ or $0.2313x^2+2.600x-54.83=0$ which can be solved using the quadratic formula (discard the negative answer) to get $x\approx8$ meaning year $1994+8=2004$
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