Answer
(a) $22.0\ million$
(b) $12.9\ million$
Work Step by Step
(a) Given $y=0.0258x^2-1.30x+23.3$. let $x=1$, we have $y=0.0258(1)^2-1.30(1)+23.3\approx22.0\ million$
(b) let $x=10$, we have $y=0.0258(10)^2-1.30(10)+23.3\approx12.9\ million$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 1 - Equations and Inequalities - 1.5 Applications and Modeling with Quadratic Equations - 1.5 Exercises - Page 133: 50
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