Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.1 Linear Equations - 1.1 Exercises: 56

Answer

$x=\dfrac{a^{2}+b^{2}}{b-a}$

Work Step by Step

$ax+b^{2}=bx-a^{2}$ Take $bx$ to the left side and $b^{2}$ to the right side: $ax-bx=-a^{2}-b^{2}$ Take out common factor $x$ from the left side and common factor $-1$ from the right side: $x(a-b)=-(a^{2}+b^{2})$ Take $a-b$ to divide the right side: $x=-\dfrac{a^{2}+b^{2}}{a-b}$ $x=\dfrac{a^{2}+b^{2}}{b-a}$
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