Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 1 - Equations and Inequalities - 1.1 Linear Equations - 1.1 Exercises - Page 93: 54

Answer

$x=\dfrac{1-2a^{2}}{1-4a}$

Work Step by Step

$\dfrac{x-1}{2a}=2x-a$ Take $2a$ to multiply the right side: $x-1=2a(2x-a)$ Take $1$ to the right side: $x=1+2a(2x-a)$ Evaluate the product on the right side: $x=1+4ax-2a^{2}$ Take $4ax$ to subtract the left side: $x-4ax=1-2a^{2}$ Take out common factor $x$ from the left side: $x(1-4a)=1-2a^{2}$ Take $1-4a$ to divide the right side: $x=\dfrac{1-2a^{2}}{1-4a}$
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