Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 20

Answer

$a.\quad x\neq 2$ $ b.\quad$ Solution set = $\emptyset$

Work Step by Step

$a.$ The denominators in the equation must not be zero: $x-2\Rightarrow x\neq 2 \qquad(*)$ $b.$ Multiply both sides with the LCD,$\quad(x-2)$ $(x-2) \displaystyle \left[ \frac{2}{x-2} \right] = (x-2) \left[ \frac{x}{x-2}-2 \right]\quad$ ... distribute and simplify $ 2=x-2(x-2)\quad$ ... distribute and simplify $2=x-2x+4$ $ 2=-x+4\quad$ ... add $x-2$ to both sides $ x=2 \quad$ ... clashes with (*), not a valid solution. Solution set = $\emptyset$
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