Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.7 - Equations - Exercise Set - Page 106: 16

Answer

Solution set = $\displaystyle \{\frac{25}{7}\}$

Work Step by Step

Multiply both sides with the LCD, $30$ $ 30 \left[\displaystyle \frac{3x}{5}-\frac{x-3}{2}\right]=30 \left[ \dfrac{x+2}{3} \right]\quad$ ... distribute and simplify $ 6(3x)+15(x-3)=10(x+2)\quad$ ... distribute and simplify $18x-15x+45=10x+20$ $ 3x+45=10x+20\quad$ ... add $-10x-45$ to both sides $3x-10x=20-45$ $-7x=-25$ $x=\displaystyle \frac{-25}{-7}=\frac{25}{7}$ Solution set = $\displaystyle \{\frac{25}{7}\}$
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