Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 70: 131

Answer

makes sense.

Work Step by Step

It is possible that a polynomial can be grouped in different ways to get the same final result. For example, $x^3+x^2+x+1=(x^3+x^2)+(x+1)=x^2(x+1)+(x+1)=(x+1)(x^2+1)$, or we can do it in a different way $x^3+x^2+x+1=(x^3+x)+(x^2+1)=x(x^2+1)+(x^2+1)=(x^2+1)(x+1)$. Thus the statement makes sense.
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