Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.4 - Polynomials - Exercise Set - Page 56: 79

Answer

$x^2+2x+2xy+2y+y^2+1$

Work Step by Step

$(x + y + 1)^2$ $=(x + y + 1)(x + y + 1)$ $=x^2+xy+x+xy+y^2+y+x + y + 1$ $=x^2+2x+2xy+2y+y^2+1$
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