Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.4 - Polynomials - Exercise Set: 73

Answer

$x^2+2xy+y^2-9$

Work Step by Step

The given expression can be written as: $[(x+y)+3][(x+y)-3].$ The expression above is of the form $(a+b)(a-b)$. RECALL: (1) $(a+b)(a-b) = a^2-b^2$ (2) $(a+b)^2=a^2+2ab+b^2$ Multiply the expression using formula (1) above with $a=x+y$ and $b=3$ to obtain: $=(x+y)^2 - 3^2 \\=(x+y)^2-9$ Square the binomial using formula (2) with $a=x$ and $b=y$ above to obtain: $=x^2+2xy+y^2-9$
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