Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Review Exercises - Page 143: 72

Answer

$\sqrt y$

Work Step by Step

$\sqrt[6] {y^3}=y^\frac{3}{6}=y^\frac{1}{2}=\sqrt y$
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