Answer
$3x^2(x+2)(x-5)$
Work Step by Step
Factor out $3x^{2}$
$=3x^{2}(x^{2}-3x-10)$
Factoring $ x^{2}+bx+c $, we search for factors (m and n) of $ c $ whose sum is $ b.$
If they (m and n) exist, we obtain $(x+m)(x+n)$.
We see that $-5$ and $+2$ are factors of $-10$, and their sum is $-3.$
= $3x^2(x+2)(x-5)$
