Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set: 81

Answer

The given equation does not represent a circle. Its graph will involve imaginary numbers

Work Step by Step

RECALL: The standard form of the equation of a circle is given as $(x-h)^2+(y-k)^2 = r^2$ where $(h, k)$ is the center $r$ is the length of the radius (distance of each point on the circle from the center). The radius of a circle cannot be negative as it would mean that the distance of the points on the circle from the center is negative. This means that the graph of the given equation is made up of imaginary numbers.
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