Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.2 Algebra Techniques for Finding Limits - 14.2 Assess Your Understanding: 20

Answer

$2$

Work Step by Step

Recall: $\lim _{x\rightarrow a}p\left( x\right) =p\left( a\right)$ Thus, $\lim _{x\rightarrow -1}\left( 8x^{5}-7x^{3}+8x^{2}+x-4\right) \\=8\times \left( -1\right) ^{5}-7\times \left( -1\right) ^{3}+8\times \left( -1\right) ^{2}+\left( -1\right) -4 \\=8 \times (-1) -7 \times (-1) + 8 \times 1 -1-4 \\=-8-(-7)+8-5 \\=-8+7+3 \\=-1+3 \\=2$
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