Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 9 - Section 9.3 - Area, Volume, and Surface Area - Exercise Set: 4

Answer

$11\frac{1}{4}ft^2$

Work Step by Step

The area of a triangle is 1\2 base times height. $A=\frac{1}{2}(4\frac{1}{2}ft)(5ft)=\frac{1}{2}(\frac{9}{2}ft)(5ft)=\frac{45}{4}ft^2=11\frac{1}{4}ft^2$
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