Answer
$9\frac{3}{4}\ yd^2$
Work Step by Step
The area of a triangle is 1\2 base times height.
$A=\frac{1}{2}(6\frac{1}{2}yd)(3yd)=\frac{1}{2}(\frac{13}{2}yd)(3yd)=\frac{39}{4}yd^2=9\frac{3}{4}yd^2$
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