## Prealgebra (7th Edition)

7$\frac{3}{5}$ hours to 1$\frac{9}{10}$ hours $\frac{7\times5 +3}{5}$ to $\frac{1\times10 +9}{10}$ = $\frac{35 +3}{5}$ to $\frac{10 +9}{10}$ = $\frac{38}{5}$ to $\frac{19}{10}$ = $\frac{38}{5}$ $\div$ $\frac{19}{10}$ = $\frac{38}{5}$ $\times$ $\frac{10}{19}$ = $\frac{38\times10}{5\times19}$ = $\frac{19\times2\times5\times2}{5\times19}$ =$\frac{2\times2}{1}$ =$\frac{4}{1}$ =4