Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 6 - Section 6.1 - Ratios and Rates - Exercise Set: 14

Answer

$\frac{4}{5}$

Work Step by Step

3$\frac{1}{3}$ to 4$\frac{1}{6}$ =$\frac{3\times3 +1}{3}$ to $\frac{4\times6 +1}{6}$ = $\frac{9 +1}{3}$ to $\frac{24 +1}{6}$ = $\frac{10}{3}$ to $\frac{25}{6}$ = $\frac{10}{3}$ $\div$ $\frac{25}{6}$ = $\frac{10}{3}$ $\times$ $\frac{6}{25}$ = $\frac{10\times6}{3\times25}$ = $\frac{5\times2\times3\times2}{3\times5\times5}$ =$\frac{2\times2}{5}$ =$\frac{4}{5}$
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