## Prealgebra (7th Edition)

$\frac{4}{5}$
3$\frac{1}{3}$ to 4$\frac{1}{6}$ =$\frac{3\times3 +1}{3}$ to $\frac{4\times6 +1}{6}$ = $\frac{9 +1}{3}$ to $\frac{24 +1}{6}$ = $\frac{10}{3}$ to $\frac{25}{6}$ = $\frac{10}{3}$ $\div$ $\frac{25}{6}$ = $\frac{10}{3}$ $\times$ $\frac{6}{25}$ = $\frac{10\times6}{3\times25}$ = $\frac{5\times2\times3\times2}{3\times5\times5}$ =$\frac{2\times2}{5}$ =$\frac{4}{5}$