Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Solving Equations Containing Fractions - Exercise Set: 16

Answer

$\frac{2}{3}$

Work Step by Step

$\frac{5}{6}$ -$\frac{1}{6}$=$\frac{5-1}{6}$ =$\frac{4}{6}$ = $\frac{2\times2}{2\times3}$=$\frac{2}{3}$
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