Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.8 - Solving Equations Containing Fractions - Exercise Set: 40

Answer

$\frac{6+7x}{3}$

Work Step by Step

2 + $\frac{7x}{3}$ =$\frac{2}{1}$ +$\frac{7x}{3}$ = $\frac{2\times3}{1\times3}$ +$\frac{7x}{3}$ LCD of 3 and 1 is 3 =$\frac{6}{3}$ +$\frac{7x}{3}$ =$\frac{6+7x}{3}$
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