Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.7 - Operations on Mixed Numbers - Exercise Set - Page 298: 37

Answer

$13\frac{13}{24}$

Work Step by Step

$3\frac{5}{8}+2\frac{1}{6}+7\frac{3}{4}$ $=3\frac{5}{8}+2\frac{1}{6}+7\frac{6}{8}$ $=3\frac{5}{8}+7\frac{6}{8}+2\frac{1}{6}$ $=10\frac{11}{8}+2\frac{1}{6}$ $=11\frac{3}{8}+2\frac{1}{6}$ $=11\frac{9}{24}+2\frac{4}{24}$ $=13\frac{13}{24}$
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