Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.7 - Operations on Mixed Numbers - Exercise Set - Page 298: 38

Answer

$16\frac{9}{10}$

Work Step by Step

$4\frac{1}{3}+9\frac{2}{5}+3\frac{1}{6}$ $=4\frac{1}{3}+3\frac{1}{6}+9\frac{2}{5}$ $=4\frac{2}{6}+3\frac{1}{6}+9\frac{2}{5}$ $=7\frac{3}{6}+9\frac{2}{5}$ $=7\frac{1}{2}+9\frac{2}{5}$ $=7\frac{5}{10}+9\frac{4}{10}$ $=16\frac{9}{10}$
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