Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set - Page 273: 64

Answer

$ \frac{11x-5}{10}$

Work Step by Step

$\frac{9x}{10}-\frac{1}{2}+\frac{x}{5}$ The least common multiplier is 10, since $5\times2=10$ Adjust the fractions based on the least common multiplier. For the first fraction, no change is needed. For the second fraction, multiply the numerator and denominator by 5. $ \frac{1}{2} \times \frac{5}{5}= \frac{5}{10}$ For the third fraction, multiply the numerator and denominator by 2. $ \frac{x}{5} \times \frac{2}{2}= \frac{2x}{10}$ Therefore, $\frac{9x}{10}- \frac{5}{10} + \frac{2x}{10}= \frac{11x-5}{10}$
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