Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.5 - Adding and Subtracting Unlike Fractions - Exercise Set: 32

Answer

$\frac{19}{40}$

Work Step by Step

LCD is 40. $\frac{5}{8}-\frac{3}{20}=\frac{5\times5}{8\times5}-\frac{3\times2}{20\times2}=\frac{25}{40}-\frac{6}{40}=\frac{25-6}{40}=\frac{19}{40}$
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