Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.3 - Multiplying and Dividing Fractions - Exercise Set - Page 250: 106

Answer

109

Work Step by Step

First column: 2 - 3 is turned into 12 - 3 as 2 < 3 12 - 3 = 9 The 9 is written in the first column and the extra 1 digit added in the tens position to the 2 is carried to the next column. Second column: 8 - 7 - additional carried 1 from the previous column = 0 The 0 is written in the second column. Third column: 8 - 7 = 1 The 1 is written in the last column. The digits we are left with are 1, 0 and 9 , so therefore the solution to the question is 109.
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