Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.3 - Multiplying and Dividing Fractions - Exercise Set - Page 250: 110

Answer

$\frac{32}{9}$

Work Step by Step

$(\frac{8}{13}\times\frac{39}{16}\times\frac{8}{9})^2\div\frac{1}{2}=(\frac{/\!\!8}{/\!\!\!13}\times\frac{/\!\!3\times/\!\!\!13}{/\!\!2\times/\!\!8}\times\frac{/\!\!2\times4}{3\times/\!\!3})^2\times\frac{2}{1}=(\frac{4}{3})^2\times\frac{2}{1}=$ $\frac{16}{9}\times\frac{2}{1}=\frac{32}{9}$
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