Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.3 - Multiplying and Dividing Fractions - Exercise Set: 45

Answer

$\frac{9}{16 }$

Work Step by Step

$(-\frac{3}{4})^{2}$= $-\frac{3}{4}$ $\times$ -$\frac{3}{4}$= The product of 2 numbers negative is a positive number =$\frac{3\times3}{4\times4}$ =$\frac{9}{16 }$
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