## Prealgebra (7th Edition)

$\frac{9}{16 }$
$(-\frac{3}{4})^{2}$= $-\frac{3}{4}$ $\times$ -$\frac{3}{4}$= The product of 2 numbers negative is a positive number =$\frac{3\times3}{4\times4}$ =$\frac{9}{16 }$