Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Section 4.3 - Multiplying and Dividing Fractions - Exercise Set - Page 247: 36

Answer

$\frac{y}{3}$

Work Step by Step

$\frac{3}{y^2}\div\frac{9}{y^3}=\frac{3}{y^2}\times\frac{y^3}{9}=\frac{3\times y^3}{y^2\times9}=\frac{3y^3}{9y^2}=\frac{3y^3\div3y^2}{9y^2\div3y^2}=\frac{y}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.