Answer
$\frac{y}{3}$
Work Step by Step
$\frac{3}{y^2}\div\frac{9}{y^3}=\frac{3}{y^2}\times\frac{y^3}{9}=\frac{3\times y^3}{y^2\times9}=\frac{3y^3}{9y^2}=\frac{3y^3\div3y^2}{9y^2\div3y^2}=\frac{y}{3}$
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