Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set - Page 189: 58

Answer

The solution is 0

Work Step by Step

4+3c =2(c+2) Apply the distributive property 4+3c=2c+4 Subtract 14from both sides 4+3c-4=2c+4-4 Simplify 3c=2c Subtract 2c from both sides 3c-2c=2c-2c c=0 The solution is 0 Check 4+3c =2(c+2) Replace c with 0 4+3$\times$ 0=2(0+2) 4+0=2$\times$2 4=4
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