Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 3 - Section 3.3 - Solving Linear Equations in One Variable - Exercise Set: 60

Answer

The solution is -5

Work Step by Step

4(2t+5)-21=7t-6 Apply the distributive property 4$\times$ 2t +4$\times$5 -21=7t-6 Multiply 8t+20-21=7t-6 Simplify 8t-1=7t-6 Add 1 to both sides . 8t-1+1=7t-6 +1 8t=7t-5 Subtract 7t from both sides 8t-7t=7t-5-7t t=-5 The solution is -5 Check 4(2t+5)-21=7t-6 Replace t with -5 4[2(-5)+5]-21=7(-5)-6 4[-10+5]-21=-35-6 4(-5)-21=-41 -20-21=-41 -41=-41
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