Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.1 - Adding and Subtracting Polynomials - Exercise Set: 41

Answer

$1\frac{2}{7}$

Work Step by Step

The phrase "Subtract (3z-$\frac{3}{7}$) from (3z+$\frac{6}{7}$)" can be translated into the expression: (3z+$\frac{6}{7}$)-(3z-$\frac{3}{7}$) Simplify: (3z+$\frac{6}{7}$)-(3z-$\frac{3}{7}$) =3z+$\frac{6}{7}$-3z+$\frac{3}{7}$ =3z-3z+$\frac{6}{7}$+$\frac{3}{7}$ =$\frac{9}{7}$ =$1\frac{2}{7}$
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