Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.1 - Adding and Subtracting Polynomials - Exercise Set: 22

Answer

-4$x^{2}$-2x-13

Work Step by Step

The phrase, "Subtract (16$x^{2}$-x+1) from (12$x^{2}$-3x-12)." can be translated to the expression: (12$x^{2}$-3x-12)-(16$x^{2}$-x+1) Simplify: (12$x^{2}$-3x-12)-(16$x^{2}$-x+1) =12$x^{2}$-3x-12-16$x^{2}$+x-1 =12$x^{2}$-16$x^{2}$-3x+x-12-1 =-4$x^{2}$-2x-13
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