Answer
$a_5=-80$
Work Step by Step
The nth term of a geometric sequence can be found using the formula:
$a_n=a_1(r^{n-1})$
where
r= common ratio
$a_1$ = first term
$a_n$ = nth term
n = term number
Substitute the given values of $a_1$, n, and $r$ to find:
$a_{5}=-5(-2)^{5-1}
\\a_{5}=-5(-2)^{4}
\\a_{5}=-5(16)
\\a_{5}=-80$