Answer
$\dfrac{3}{4}, 1, \dfrac{5}{4}, \dfrac{3}{2}, \dfrac{7}{4}, 2$
Work Step by Step
The arithmetic sequence has:
A first term of 3/4
A common difference of 1/4
List the first 6 terms by adding $\frac{1}{4}$ to get the next term:
$\dfrac{3}{4}, 1, \dfrac{5}{4}, \dfrac{6}{4}= \dfrac{3}{2}, \dfrac{7}{4}, 2$
